module test_Pipelining ( input CLK, input RSTn, output reg [7:0]result ); reg [7:0]x,y; reg [3:0]i; always @(posedge CLK or negedge RSTn) if(!RSTn) begin x <= 8'd0; y <= 8'd0; i <= 4'd0; end else case(i) 0: begin x <= 8'd1; y <= 8'd1; i <= i + 1'b1; end 1: begin x <= 8'd2; y <= 8'd2; i <= i + 1'b1; end 2: begin x <= 8'd3; y <= 8'd3; i <= i + 1'b1; end 3: begin x <= 8'd0; y <= 8'd0; i <= i; end endcase reg [7:0]result0; always @(posedge CLK or negedge RSTn) if(!RSTn) begin result0 <= 8'd0; end else begin result0 <= x + y; end reg [7:0]result1; always @(posedge CLK or negedge RSTn) if(!RSTn) begin result1 <= 8'd0; end else begin result1 <= result0 * 8'd3; end always @(posedge CLK or negedge RSTn) if(!RSTn) begin result <= 8'd0; end else begin result <= result1 + 8'd5; end endmodule

将公式(x + y) * 3 + 5,猜分成3个步骤
1、result0 <= x + y;
2、result1 <= result0 * 8'd3;
3、result <= result1 + 8'd5;

result0延时x，y一个周期；
result1延时result0一个周期；
result延时result1一个周期；

那么，result延时x，y 3个周期；且一一对应！！

因为x，y是源源不断的输入（每个周期改变一次）
所以 result在3个周期后，是源源不断的输出～～！！

总结：1、潜伏周期 = 步骤数。
2、最后一个数据的输入时刻 + 潜伏周期数（或者步骤数） 就是整个流水操作的完成时刻。

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